Trailing Zeroes in the factorial of a Number.

Problem:- Write a program to find the number of zeroes at the end of n!  i.e.  the number of trailing zeroes in the factorial of a number.

Solution:-

#include<stdio.h>

int main()

{

   int n,count=0,i;

    scanf("%d",&n);

        for(i=5;n/i>=1;i*=5)

            count+=n/i;

        printf("No. of zeroes at the end of %d! are:-%d\n",n,count);

return 0;

}